[FFmpeg-user] Meaning of ffprobe output

Carl Eugen Hoyos ceffmpeg at gmail.com
Fri Jan 11 02:47:38 EET 2019

2019-01-11 0:39 GMT+01:00, Ulf Zibis <Ulf.Zibis at gmx.de>:

> can anybody explain me the data of ffprobe, I don't find enough hints in
> the docu. E.g.:
> $ ffprobe CYD_copy.vob
> Input #0, mpeg, from 'CYD_copy.vob':
>   Duration: 01:16:20.74, start: 0.500000, bitrate: 7068 kb/s
>     Stream #0:0[0x80]: Audio: ac3, 48000 Hz, stereo, fltp, 256 kb/s
>     Stream #0:1[0x1e0]: Video: mpeg2video (Main), yuv420p(tv, bt470bg,
> top first), 704x576 [SAR 12:11 DAR 4:3], 25 fps, 25 tbr, 90k tbn, 50 tbc
> What is:

> tv
> bt470bg

Colour-space related information.

> tbr

The least common multiple of all framerates in the stream, a guess.

> tbn

This is the container timebase, 90k for mpeg streams.

> tbc

This is the codec timebase.

> I'm also wondering, why Stream #0:1 is the video, as it was created by
> $ ffmpeg -ss 00:03 -t 01:16:20 -i
> "concat:001-C001/CYD-001.vob|001-C002/CYD-001.vob|..."

vob has no stream order, "0:1" simply means "second stream
found be FFmpeg".

> -movflags +faststart -c copy CYD_copy.vob

Sadly, output option cannot (easily) be checked for correctness.
Using options that cannot have an effect may reduce your
chance to get good help here (consider the increased time it
needs to understand what's going on / what your intentions are).

Not necessarily related: "-c copy" cannot change anything
about fields ("half-frames"), libx264 does not support PAFF

Carl Eugen

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