[FFmpeg-user] xmedian questions
Mark Filipak (ffmpeg)
markfilipak at bog.us
Fri Jan 1 03:25:40 EET 2021
1, Median? Really? (Or maybe really average?)
For inputs = 239+15+15+15:
median = (239+15)/2 = 127
average = (239+15+15+15)/4 = 71
For inputs = 239+239+239+15:
median = (239+15)/2 = 127 (again)
average = (239+239+239+15)/4 = 183
Or is the median windowed?
For inputs = 239+15+15+15:
windowed median = ((239+15)/2+(15+15)/2)/2 = 71
For inputs = 239+239+239+15:
windowed median = ((239+239)/2+(239+15)/2)/2 = 183
Hmmm... Windowed median is actually average, isn't it?
1.1, If the number of inputs is odd, will the calculation skewed in favor of the final input in the
windowed median calculation?) What is the real method that xmedian is using?
1.2, How does the value of 'percentile' figure into the calculations?
2, Why isn't "inputs=2" allowed?
From ffmpeg.org/ffmpeg-filters.html#xmedian
=====
11.240 xmedian
Pick median pixels from several input videos.
The filter accepts the following options:
inputs
Set number of inputs. Default is 3. Allowed range is from 3 to 255. If number of inputs is even
number, than result will be mean value between two median values.
planes
Set which planes to filter. Default value is 15, by which all planes are processed.
percentile
Set median percentile. Default value is 0.5. Default value of 0.5 will pick always median
values, while 0 will pick minimum values, and 1 maximum values.
=====
For what it's worth, here's how I document it:
xmedian ...Pick median pixel values from several video streams.
xmedian=inputs=3:planes=15:percentile=0.5" ...defaults
| | |
| | value to pick = max..median..min (1..0.5..0)
| color planes to pick = red+green+blue+alpha (sum of 1+2+4+8)
number of input streams = 3..255
Of course, "value to pick = max..median..min (1..0.5..0)" is insufficient, isn't it?
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