[FFmpeg-user] How can I remove the first 30 seconds of 3000 MP3 files

[Børge Wedel Müller]

Hi Again
When I run the command below, I got a "larger than sign" eg this sign ">"

What Iis I doing wrong?
Best
/Børge Wedel Müller



Den 23. januar 2022 kl. 19.22.19 +01.00, skrev LuKaRo <lists at lrose.de>:

> Hi,
> 
> you can use standard Unix methods for batch processing, e.g. in bash:
> 
> for i in *.mp3; do ffmpeg -ss 00:00:30.000 -i "$i" -c copy "$(basename $i .mp3)-output.mp3"
> 
> This will cut the first 30 seconds from each file ending in .mp3, creating a file with the same name and -output at the end. Instead of -c copy, you can add any additional ffmpeg arguments regarding the output.
> 
> If you want to leverage parallel processing, you can use xargs instead (note that this will disable interactive input in ffmpeg, e.g. asking for overwrites):
> 
> ls *.mp3 | xargs -P 4 -I '{}' bash -c 'ffmpeg -ss 00:00:30.000 -i "{}" -c copy "$(basename {} .mp3)-output.mp3"
> 
> Again, replace -c copy by any output parameters you'd like to use, and replace -P 4 by the number of processes you want to start in parallel.
> 
> Let us know if you have any further questions.
> 
> Kind regards,
> 
> LuKaRo
> 
> On 1/23/22 17:28, Børge Wedel Müller wrote:
> 
> > Hi
> > I have searched over and over again, so this is last resort :-)
> > I have approx 3000 audio files MP3, and I need to remove the first 30 seconds of each and everyone of the files.
> > 
> > I am using a LINUX system. (Debian)
> > I hope you can learn me how to remove these first annoying 30 seconds i one batch.
> > 
> > Thanks.
> > 
> > Best
> > /Børge Wedel Müller
> > 
> > 
> > 
> > 
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