[FFmpeg-cvslog] r12286 - trunk/libavcodec/ac3dec.c
Ivan Kalvachev
ikalvachev
Sat Mar 1 16:55:35 CET 2008
On Sat, Mar 1, 2008 at 5:48 PM, jbr <subversion at mplayerhq.hu> wrote:
> Author: jbr
> Date: Sat Mar 1 16:48:18 2008
> New Revision: 12286
>
> Log:
> pre-calculate downmix coefficient sums. 2% faster 5.1-to-stereo downmixing.
>
> Modified:
> trunk/libavcodec/ac3dec.c
>
> Modified: trunk/libavcodec/ac3dec.c
> ==============================================================================
> --- trunk/libavcodec/ac3dec.c (original)
> +++ trunk/libavcodec/ac3dec.c Sat Mar 1 16:48:18 2008
> @@ -154,6 +154,7 @@ typedef struct {
> int center_mix_level; ///< Center mix level index
> int surround_mix_level; ///< Surround mix level index
> float downmix_coeffs[AC3_MAX_CHANNELS][2]; ///< stereo downmix coefficients
> + float downmix_coeff_sum[2]; ///< sum of downmix coeffs for each output channel
> float dynamic_range[2]; ///< dynamic range
> int cpl_coords[AC3_MAX_CHANNELS][18]; ///< coupling coordinates
> int num_cpl_bands; ///< number of coupling bands
> @@ -402,6 +403,12 @@ static void set_downmix_coeffs(AC3Decode
> int nf = s->channel_mode - 4;
> s->downmix_coeffs[nf][0] = s->downmix_coeffs[nf+1][1] = smix;
> }
> +
> + s->downmix_coeff_sum[0] = s->downmix_coeff_sum[1] = 0.0f;
> + for(i=0; i<s->fbw_channels; i++) {
> + s->downmix_coeff_sum[0] += s->downmix_coeffs[i][0];
> + s->downmix_coeff_sum[1] += s->downmix_coeffs[i][1];
> + }
> }
>
> /**
> @@ -732,18 +739,16 @@ static inline void do_imdct(AC3DecodeCon
> static void ac3_downmix(AC3DecodeContext *s)
> {
> int i, j;
> - float v0, v1, s0, s1;
> + float v0, v1;
>
> for(i=0; i<256; i++) {
> - v0 = v1 = s0 = s1 = 0.0f;
> + v0 = v1 = 0.0f;
> for(j=0; j<s->fbw_channels; j++) {
> v0 += s->output[j][i] * s->downmix_coeffs[j][0];
> v1 += s->output[j][i] * s->downmix_coeffs[j][1];
> - s0 += s->downmix_coeffs[j][0];
> - s1 += s->downmix_coeffs[j][1];
> }
> - v0 /= s0;
> - v1 /= s1;
> + v0 /= s->downmix_coeff_sum[0];
> + v1 /= s->downmix_coeff_sum[1];
You know, multiply is usually faster than division, so if these sums
are constant, you can probably calculate reciprocals and multiply in
the loop.
{sr0=1/s0;...; v0*=sr0};
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