Ivan Kalvachev wrote: > You know, multiply is usually faster than division, so if these sums > are constant, you can probably calculate reciprocals and multiply in > the loop. > {sr0=1/s0;...; v0*=sr0}; Thanks. It definitely helps. :) Updated 5.1-to-stereo benchmark: liba52 1.756 ffac3 2.420 -Justin