[FFmpeg-user] scaling failed: height must be an integer

[Martin Schmidt]

You can also do this: "-vf scale=1280:trunc(ow/a/2)*2"

It will always make sure that the resulting height is divisible by 2.
Output width (ow) is divided by the aspect ratio (a) and then by 2.
Then "trunc" truncates digits after the decimal point and in the end
multiply by two.

Am 28.07.2015 um 10:16 schrieb Moritz Barsnick:
> On Tue, Jul 28, 2015 at 10:07:02 +0200, Moritz Barsnick wrote:
> D'uh, wrong quote. This I meant to quote:
>
>      If one of the values is -n with n > 1, the scale filter will also
>      use a value that maintains the aspect ratio of the input image,
>      calculated from the other specified dimension. After that it will,
>      however, make sure that the calculated dimension is divisible by n
>      and adjust the value if necessary.
>
> This stands.
>
> Cheers,
> Moritz
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